Номер 162 ГДЗ алгебра 8 класс Макарычев

№162.
a)

$$
\begin{gathered}
\frac{1}{2} \cdot \frac{2 x^2-x y}{0.36 x^2-0.25 y^2} \\
\frac{2 x^2-x y}{2\left(0.18 x^2-0.125 y^2\right)}=\frac{2 x^2-x y}{0.36 x^2-0.25 y^2} \\
0.36 x^2-0.25 y^2=(0.6 x-0.5 y)(0.6 x+0.5 y) \\
\frac{2 x(x-0.5 y)}{(0.6 x-0.5 y)(0.6 x+0.5 y)}=\frac{20 x}{6 x+5 y}
\end{gathered}
$$

б)

$$
\begin{gathered}
\frac{4.5 a+4 x}{0.81 a^2-0.64 x^2} \\
0.81 a^2-0.64 x^2=(0.9 a-0.8 x)(0.9 a+0.8 x) \\
\frac{4.5 a+4 x}{(0.9 a-0.8 x)(0.9 a+0.8 x)} \\
\frac{50}{9 a-8 x}
\end{gathered}
$$